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(Delphi DLL) Parse Multipart Binary Http ResponseThis example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf.
uses Winapi.Windows, Winapi.Messages, System.SysUtils, System.Variants, System.Classes, Vcl.Graphics, Vcl.Controls, Vcl.Forms, Vcl.Dialogs, Vcl.StdCtrls, Http, HttpRequest, BinData, HttpResponse, Mime; ... procedure TForm1.Button1Click(Sender: TObject); var success: Boolean; http: HCkHttp; req: HCkHttpRequest; resp: HCkHttpResponse; respBody: HCkBinData; mime: HCkMime; numParts: Integer; part0: HCkMime; xmlStr: PWideChar; part1: HCkMime; zipData: HCkBinData; begin // This example requires the Chilkat API to have been previously unlocked. // See Global Unlock Sample for sample code. http := CkHttp_Create(); req := CkHttpRequest_Create(); // ... // Insert code here to construct some kind of HTTP request. // this example is to show how to parse a particular kind of response. // ... // ... // Send the request (whatever it may be in your case) to get the HTTP response object. resp := CkHttp_SynchronousRequest(http,'www.somedomain.com',443,True,req); if (CkHttp_getLastMethodSuccess(http) <> True) then begin Memo1.Lines.Add(CkHttp__lastErrorText(http)); Exit; end; // Get the response body (which is expected to be binary) respBody := CkBinData_Create(); CkHttpResponse_GetBodyBd(resp,respBody); CkHttpResponse_Dispose(resp); // For this example, the response body contains something like this: // ------=_Part_21302_2029949381.1547401515443 // Content-Type: application/xop+xml; charset=UTF-8; type="text/xml" // Content-Transfer-Encoding: 8bit // Content-ID: <rootpart@ws.jboss.org> // // <env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'><env:Header></env:Header><env:Body>...</env:Body></env:Envelope> // ------=_Part_21302_2029949381.1547401515443 // Content-Type: application/octet-stream // Content-Transfer-Encoding: binary // Content-Id: <fileArchivio-7d302908-4d64-43d3-bf4e-79ce806d43b3@ws.jboss.org> // // BINARY_CONTENT_HERE... // // ------=_Part_21302_2029949381.1547401515443-- // // Load it into a Chilkat MIME object. mime := CkMime_Create(); success := CkMime_LoadMimeBd(mime,respBody); if (success <> True) then begin Memo1.Lines.Add(CkMime__lastErrorText(mime)); Exit; end; numParts := CkMime_getNumParts(mime); if (numParts < 2) then begin Memo1.Lines.Add('Expected multipart MIME with at least 2 sub-parts.'); Exit; end; // Get the 1st sub-part, which is the XML. part0 := CkMime_GetPart(mime,0); // Should be OK because we checked NumParts above.. xmlStr := CkMime__getBodyDecoded(part0); Memo1.Lines.Add(xmlStr); Memo1.Lines.Add('----'); CkMime_Dispose(part0); // Save the 2nd part to a file. (It is a .zip file in our test case..) part1 := CkMime_GetPart(mime,1); success := CkMime_SaveBody(part1,'qa_output/attachedZip.zip'); // Alternatively, we could extract the binary data to a BinData and use elsewhere.. zipData := CkBinData_Create(); success := CkMime_GetBodyBd(part1,zipData); success := CkBinData_WriteFile(zipData,'qa_output/attachedZip_again.zip'); CkMime_Dispose(part1); Memo1.Lines.Add('OK.'); CkHttp_Dispose(http); CkHttpRequest_Dispose(req); CkBinData_Dispose(respBody); CkMime_Dispose(mime); CkBinData_Dispose(zipData); end; |
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