Delphi ActiveX Requires Chilkat v11.0.0+
Delphi ActiveX
Duplicate PHP RSA Encryption
See more RSA Examples
Demonstrates how to duplicate the following PHP function.Chilkat Delphi ActiveX Downloads
var
success: Integer;
rsaMOD: WideString;
rsaEXP: WideString;
bdMod: TChilkatBinData;
bdExp: TChilkatBinData;
xml: TChilkatXml;
pubkey: TPublicKey;
rsa: TChilkatRsa;
plainText: WideString;
cipherText: WideString;
begin
success := 0;
// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.
// Duplicate the following PHP code:
//
// public function encryptRSA($plainText,$rsaMOD,$pubKEY){
// $rsa = new RSA();
// $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1);
// $publicKey = [
// 'e' => new BigInteger($pubKEY,16),
// 'n' => new BigInteger($rsaMOD,16)
// ];
//
// $rsa->loadKey($publicKey);
// $ciphertext = $rsa->encrypt($plainText);
// return bin2hex($ciphertext);
// }
//
// $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
// $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"
// $pubKEY="010001"
// We have the RSA modulus in hex
rsaMOD := 'F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673';
// The RSA exponent in hex is "010001", which is 65537 in decimal. It's typically the exponent that is always used.
rsaEXP := '010001';
// Get the RSA modulus and exponent in base64.
bdMod := TChilkatBinData.Create(Self);
bdExp := TChilkatBinData.Create(Self);
success := bdMod.AppendEncoded(rsaMOD,'hex');
success := bdExp.AppendEncoded(rsaEXP,'hex');
// Build the XML representation of the RSA public key
xml := TChilkatXml.Create(Self);
xml.Tag := 'RSAPublicKey';
xml.UpdateChildContent('Modulus',bdMod.GetEncoded('base64'));
xml.UpdateChildContent('Exponent',bdExp.GetEncoded('base64'));
// Load the RSA public key into a Chilkat public key object.
pubkey := TPublicKey.Create(Self);
success := pubkey.LoadFromString(xml.GetXml());
// Setup the RSA object for encryption and do it..
rsa := TChilkatRsa.Create(Self);
rsa.VerboseLogging := 1;
success := rsa.UsePublicKey(pubkey.ControlInterface);
// Use PKCSv1.5 padding
rsa.PkcsPadding := 1;
// Encrypt and return the string as hex.
rsa.EncodingMode := 'hex';
plainText := 'key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678';
cipherText := rsa.EncryptStringENC(plainText,0);
if (rsa.LastMethodSuccess = 0) then
begin
Memo1.Lines.Add(rsa.LastErrorText);
Exit;
end;
// Note: The PKCSv1_5 padding incorporates random bytes. Therefore, the RSA encryption will produce different results each time -- all of which are valid
// and decrypt correctly to the same original text.
Memo1.Lines.Add(cipherText);