Sample code for 30+ languages & platforms
C#

Iterate over Direct Children with a Specific Tag

See more XML Examples

Demonstrates how to iterate over direct children having a specific tag.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Chilkat C# Downloads

C#
bool success = false;

Chilkat.Xml xml = new Chilkat.Xml();
Chilkat.Xml child = null;
int numWithTag;
int i;

// The sample input XML is available at http://www.chilkatsoft.com/data/fruit.xml
success = xml.LoadXmlFile("fruit.xml");
if (success != true) {
    Debug.WriteLine(xml.LastErrorText);
    return;
}

//  Get the number of direct children having the tag "fruit"
numWithTag = xml.NumChildrenHavingTag("fruit");

if (numWithTag > 0) {

    for (i = 0; i <= numWithTag - 1; i++) {
        child = xml.GetNthChildWithTag("fruit",i);
        Debug.WriteLine(Convert.ToString(i) + ": " + child.Tag + " : " + child.Content);

    }

    Debug.WriteLine("-----");

    // Do the same as the above loop, but instead of creating
    // a new object instance for each child, call GetNthChildWithTag2 to
    // update the object's reference instead.
    for (i = 0; i <= numWithTag - 1; i++) {
        // Navigate to the Nth child.  
        success = xml.GetNthChildWithTag2("fruit",i);
        Debug.WriteLine(Convert.ToString(i) + ": " + xml.Tag + " : " + xml.Content);
        // Navigate back up to the parent:
        success = xml.GetParent2();
    }

    Debug.WriteLine("-----");
}