C#

Parsing XML Children Having Identical Tags

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Demonstrates how to deal with XML where child elements may have identical tags. C#

bool success = false;

// This example will get the phoneNumber's and groupMembershihpInfo's from the following XML:

// <?xml version="1.0" encoding="UTF-8" ?>
// <someEntries>
//     <entry>
//         <id>123</id>
//         <updated>2017-07-19T05:19:57.761Z</updated>
//         <app:edited xmlns:app="http://www.w3.org/2007/app">2017-07-19T05:19:57.761Z</app:edited>
//         <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact"/>
//         <title>George Costanza</title>
//          <gd:name>
//             <gd:fullName>George Costanza</gd:fullName>
//             <gd:givenName>George</gd:givenName>
//             <gd:familyName>Costanza</gd:familyName>
//         </gd:name>
//         <gd:phoneNumber rel="http://schemas.google.com/g/2005#home">(555) 123-4567</gd:phoneNumber>
//         <gd:phoneNumber rel="http://schemas.google.com/g/2005#mobile">(555) 444-8877</gd:phoneNumber>
//         <gd:phoneNumber rel="http://schemas.google.com/g/2005#work">(555) 678-1111</gd:phoneNumber>
//         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/123"/>
//         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/456"/>
//     </entry>
// </someEntries>
// 

Chilkat.Xml xml = new Chilkat.Xml();

success = xml.LoadXmlFile("qa_data/xml/georgeCostanza.xml");

int numPhoneNumbers = xml.NumChildrenHavingTag("entry|*:phoneNumber");
int i = 0;
while (i < numPhoneNumbers) {
    Chilkat.Xml xPhoneNumber = xml.GetNthChildWithTag("entry|*:phoneNumber",i);
    Debug.WriteLine(xPhoneNumber.Content);

    i = i + 1;
}

Debug.WriteLine("----");

int numGroupMemberships = xml.NumChildrenHavingTag("entry|*:groupMembershipInfo");
i = 0;
while (i < numGroupMemberships) {
    Chilkat.Xml xMembership = xml.GetNthChildWithTag("entry|*:groupMembershipInfo",i);
    Debug.WriteLine(xMembership.GetAttrValue("href"));

    i = i + 1;
}