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      (C#) HTTP POST and Stream Response to FileDemonstrates how to send an HTTP POST and stream the response body directly to a file. 
 // This example requires the Chilkat API to have been previously unlocked. // See Global Unlock Sample for sample code. Chilkat.Rest rest = new Chilkat.Rest(); Chilkat.Url url = new Chilkat.Url(); // This URL will emit a response that echos the query params (name and age) url.ParseUrl("https://www.chilkatsoft.com/readPost.asp"); // Connect to the web server bool bAutoReconnect = true; bool success = rest.Connect(url.Host,url.Port,url.Ssl,bAutoReconnect); if (success != true) { Debug.WriteLine(rest.LastErrorText); return; } rest.AddQueryParam("name","John"); rest.AddQueryParam("age","33"); // Send the HTTP POST. success = rest.SendReqFormUrlEncoded("POST",url.Path); if (success != true) { Debug.WriteLine(rest.LastErrorText); return; } // Read the response header. int responseStatusCode = rest.ReadResponseHeader(); if (responseStatusCode < 0) { Debug.WriteLine(rest.LastErrorText); return; } Debug.WriteLine("Response status code = " + Convert.ToString(responseStatusCode)); // We expect a 200 response status if the file data is coming. // Otherwise, we'll get a string response body with an error message(or no response body). if (responseStatusCode == 200) { Chilkat.Stream bodyStream = new Chilkat.Stream(); // The stream's sink will be a file. bodyStream.SinkFile = "qa_output/out.txt"; // Read the response body to the stream. Given that we've // set the stream's sink to a file, it will stream directly // to the file. success = rest.ReadRespBodyStream(bodyStream,true); if (success != true) { Debug.WriteLine(rest.LastErrorText); return; } Debug.WriteLine("Successfully streamed the response to a file."); } else { string errResponse = rest.ReadRespBodyString(); if (rest.LastMethodSuccess != true) { Debug.WriteLine(rest.LastErrorText); } else { Debug.WriteLine(errResponse); } }  | 
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