C++

Resolve Domain to IP Address

See more DNS Examples

Demonstrates how to perform a DNS query to obtain A records for resolving a domain name to an IPv4 address. C++

#include <CkDns.h>
#include <CkJsonObject.h>

void ChilkatSample(void)
    {
    bool success = false;

    CkDns dns;

    CkJsonObject json;
    json.put_EmitCompact(false);

    success = dns.Query("A","microsoft.com",json);
    if (success == false) {
        std::cout << dns.lastErrorText() << "\r\n";
        return;
    }

    std::cout << json.emit() << "\r\n";

    // Sample response.
    // Parsing code below..

    // {
    //   "answer": {
    //     "a": [
    //       {
    //         "name": "microsoft.com",
    //         "ttl": 1528,
    //         "ipv4": "20.112.250.133"
    //       },
    //       {
    //         "name": "microsoft.com",
    //         "ttl": 1528,
    //         "ipv4": "20.231.239.246"
    //       },
    //       {
    //         "name": "microsoft.com",
    //         "ttl": 1528,
    //         "ipv4": "20.76.201.171"
    //       },
    //       {
    //         "name": "microsoft.com",
    //         "ttl": 1528,
    //         "ipv4": "20.70.246.20"
    //       },
    //       {
    //         "name": "microsoft.com",
    //         "ttl": 1528,
    //         "ipv4": "20.236.44.162"
    //       }
    //     ]
    //   }
    // }

    // Use this online tool to generate parsing code from sample JSON: 
    // Generate Parsing Code from JSON

    const char *name = 0;
    int ttl;
    const char *ipv4 = 0;

    int i = 0;
    int count_i = json.SizeOfArray("answer.a");
    while (i < count_i) {
        json.put_I(i);
        name = json.stringOf("answer.a[i].name");
        ttl = json.IntOf("answer.a[i].ttl");
        ipv4 = json.stringOf("answer.a[i].ipv4");
        i = i + 1;
    }
    }