C++

Parse Multipart Binary Http Response

See more HTTP Examples

This example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf. C++

#include <CkHttp.h>
#include <CkHttpRequest.h>
#include <CkHttpResponse.h>
#include <CkBinData.h>
#include <CkMime.h>

void ChilkatSample(void)
    {
    bool success = false;

    //  This example requires the Chilkat API to have been previously unlocked.
    //  See Global Unlock Sample for sample code.

    CkHttp http;
    CkHttpRequest req;

    //  ...
    //  Insert code here to construct some kind of HTTP request.
    //  this example is to show how to parse a particular kind of response.
    //  ...
    //  ...

    //  Send the request (whatever it may be in your case) to get the HTTP response object.
    CkHttpResponse resp;
    success = http.HttpSReq("www.somedomain.com",443,true,req,resp);
    if (success == false) {
        std::cout << http.lastErrorText() << "\r\n";
        return;
    }

    //  Get the response body (which is expected to be binary)
    CkBinData respBody;
    resp.GetBodyBd(respBody);

    //  For this example, the response body contains something like this:

    //  ------=_Part_21302_2029949381.1547401515443
    //  Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
    //  Content-Transfer-Encoding: 8bit
    //  Content-ID: <rootpart@ws.jboss.org>
    //  
    //  <env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'><env:Header></env:Header><env:Body>...</env:Body></env:Envelope>
    //  ------=_Part_21302_2029949381.1547401515443
    //  Content-Type: application/octet-stream
    //  Content-Transfer-Encoding: binary
    //  Content-Id: <fileArchivio-7d302908-4d64-43d3-bf4e-79ce806d43b3@ws.jboss.org>
    //  
    //  BINARY_CONTENT_HERE...
    //  
    //  ------=_Part_21302_2029949381.1547401515443--
    //  

    //  Load it into a Chilkat MIME object.
    CkMime mime;
    success = mime.LoadMimeBd(respBody);
    if (success == false) {
        std::cout << mime.lastErrorText() << "\r\n";
        return;
    }

    int numParts = mime.get_NumParts();
    if (numParts < 2) {
        std::cout << "Expected multipart MIME with at least 2 sub-parts." << "\r\n";
        return;
    }

    //  Get the 1st sub-part, which is the XML.

    CkMime part0;
    mime.PartAt(0,part0);

    //  Should be OK because we checked NumParts above..
    const char *xmlStr = part0.getBodyDecoded();
    std::cout << xmlStr << "\r\n";
    std::cout << "----" << "\r\n";

    //  Save the 2nd part to a file.  (It is a .zip file in our test case..)

    CkMime part1;
    mime.PartAt(1,part1);

    success = part1.SaveBody("qa_output/attachedZip.zip");

    //  Alternatively, we could extract the binary data to a BinData and use elsewhere..
    CkBinData zipData;
    success = part1.GetBodyBd(zipData);
    success = zipData.WriteFile("qa_output/attachedZip_again.zip");

    std::cout << "OK." << "\r\n";
    }