(Chilkat2-Python) Iterate over Direct Child Nodes by Index

Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Chilkat2 Python Downloads install with pip pip3 install chilkat2 or download... Python Module for Windows, Linux, Alpine Linux, MacOS, Solaris

import sys
import chilkat2

xml = chilkat2.Xml()

# The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml")
if (success != True):
    print(xml.LastErrorText)
    sys.exit()

# The NumChildren property contains the number of direct
# child nodes.  Note: The child nodes under "xyz" are NOT
# direct children of "root".  Therefore, the "root" node has
# 7 direct children
print("NumChildren = " + str(xml.NumChildren))

# Iterate over the direct children by index. The first child
# is at index 0.

for i in range(0,xml.NumChildren):
    #  access the tag and content directly by index:
    print(str(i) + ": " + xml.GetChildTagByIndex(i) + " : " + xml.GetChildContentByIndex(i))

print("-----")

# Do the same as the above loop, but get the child node
# and access the Tag and Content properties:
for i in range(0,xml.NumChildren):
    # child is a CkXml
    child = xml.GetChild(i)
    print(str(i) + ": " + child.Tag + " : " + child.Content)

print("-----")

# Do the same as the above loop, but instead of creating
# a new object instance for each child, call GetChild2 to
# update the object's reference instead.
for i in range(0,xml.NumChildren):
    # Navigate to the Nth child.  
    success = xml.GetChild2(i)
    print(str(i) + ": " + xml.Tag + " : " + xml.Content)
    # Navigate back up to the parent:
    success = xml.GetParent2()

print("-----")

# Notice that the Content of the "xyz" node is empty.  This is correct.
# The "xyz" node has no Content, but 2 direct children