(Chilkat2-Python) S3 Find Bucket Region

Demonstrates how to find out the region of an S3 bucket.

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import sys
import chilkat2

# This requires the Chilkat API to have been previously unlocked.
# See Global Unlock Sample for sample code.

rest = chilkat2.Rest()

# Connect to the Amazon AWS REST server using the correct region (in this example, "us-west-2")
bTls = True
port = 443
bAutoReconnect = True
success = rest.Connect("s3.amazonaws.com",port,bTls,bAutoReconnect)

# Provide AWS credentials for the REST call.
authAws = chilkat2.AuthAws()
authAws.AccessKey = "AWS_ACCESS_KEY"
authAws.SecretKey = "AWS_SECRET_KEY"
authAws.ServiceName = "s3"
success = rest.SetAuthAws(authAws)

# The bucket name we want to know about is set in the HOST header.
# In this example, we want to find the region for the "chilkat.qa" bucket.
rest.Host = "chilkat.qa.s3.amazonaws.com"

# Send the GET request to query the bucket location.
strResult = rest.FullRequestNoBody("GET","/?location")
if (rest.LastMethodSuccess != True):
    print(rest.LastErrorText)
    sys.exit()

responseStatusCode = rest.ResponseStatusCode
print("Response status code = " + str(responseStatusCode))
if (responseStatusCode != 200):
    print(rest.ResponseHeader)
    print(strResult)
    print("Failed.")
    sys.exit()

print(strResult)

# The result contains XML like this:
# <?xml version="1.0" encoding="UTF-8"?>
# <LocationConstraint xmlns="http://s3.amazonaws.com/doc/2006-03-01/">us-west-2</LocationConstraint>

# Get the "us-west-2" from the XML
xml = chilkat2.Xml()
success = xml.LoadXml(strResult)
print("region = " + xml.Content)