(Chilkat2-Python) Get the Root of a JSON Document

Demonstrates how to get back to the JSON root object from anywhere in the JSON document. This example uses the following JSON document:

{
  "flower": "tulip",
  "abc":
    {
    "x": [
       { "a" : 1 },
       { "b1" : 100, "b2" : 200 },
       { "c" : 3 }
    ],
    "y": 200,
    "z": 200
    }
}

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import sys
import chilkat2

json = chilkat2.JsonObject()

jsonStr = "{\"flower\": \"tulip\",\"abc\":{\"x\": [{ \"a\" : 1 },{ \"b1\" : 100, \"b2\" : 200 },{ \"c\" : 3 }],\"y\": 200,\"z\": 200}}"

success = json.Load(jsonStr)
if (success != True):
    print(json.LastErrorText)
    sys.exit()

# Get the "abc" object.
# abcObj is a CkJsonObject
abcObj = json.ObjectOf("abc")
if (json.LastMethodSuccess == False):
    print("abc object not found.")
    sys.exit()

# Side note: The JSON of a sub-part of the document can be emitted from any JSON object:
abcObj.EmitCompact = False
print(abcObj.Emit())

# Navigate to the "x" array
# xArray is a CkJsonArray
xArray = abcObj.ArrayOf("x")
# We'll skip the null check and assume it's non-null...

# Navigate to the 2nd object contained within the array.  This contains members b1 and b2
# bObj is a CkJsonObject
bObj = xArray.ObjectAt(1)
# We'll skip the null check and assume it's non-null...

# Show that we're at "b1/b2".
# The value of "b1" should be "200"
print("b2 = " + str(bObj.IntOf("b2")))

# Now go back to the JSON doc root:
# docRoot is a CkJsonObject
docRoot = bObj.GetDocRoot()
# We'll skip the null check and assume it's non-null...

# Pretty-print the JSON doc from the root to show that this is indeed the root.
docRoot.EmitCompact = False
print(docRoot.Emit())