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(Chilkat2-Python) HTTP POST and Stream Response to FileDemonstrates how to send an HTTP POST and stream the response body directly to a file.
import sys import chilkat2 # This example requires the Chilkat API to have been previously unlocked. # See Global Unlock Sample for sample code. rest = chilkat2.Rest() url = chilkat2.Url() # This URL will emit a response that echos the query params (name and age) url.ParseUrl("https://www.chilkatsoft.com/readPost.asp") # Connect to the web server bAutoReconnect = True success = rest.Connect(url.Host,url.Port,url.Ssl,bAutoReconnect) if (success != True): print(rest.LastErrorText) sys.exit() rest.AddQueryParam("name","John") rest.AddQueryParam("age","33") # Send the HTTP POST. success = rest.SendReqFormUrlEncoded("POST",url.Path) if (success != True): print(rest.LastErrorText) sys.exit() # Read the response header. responseStatusCode = rest.ReadResponseHeader() if (responseStatusCode < 0): print(rest.LastErrorText) sys.exit() print("Response status code = " + str(responseStatusCode)) # We expect a 200 response status if the file data is coming. # Otherwise, we'll get a string response body with an error message(or no response body). if (responseStatusCode == 200): bodyStream = chilkat2.Stream() # The stream's sink will be a file. bodyStream.SinkFile = "qa_output/out.txt" # Read the response body to the stream. Given that we've # set the stream's sink to a file, it will stream directly # to the file. success = rest.ReadRespBodyStream(bodyStream,True) if (success != True): print(rest.LastErrorText) sys.exit() print("Successfully streamed the response to a file.") else: errResponse = rest.ReadRespBodyString() if (rest.LastMethodSuccess != True): print(rest.LastErrorText) else: print(errResponse) |
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