Chilkat2-Python

HTTP POST and Stream Response to File

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Demonstrates how to send an HTTP POST and stream the response body directly to a file. Chilkat2-Python

import sys
import chilkat2

success = False

# This example requires the Chilkat API to have been previously unlocked.
# See Global Unlock Sample for sample code.

rest = chilkat2.Rest()

url = chilkat2.Url()
# This URL will emit a response that echos the query params (name and age)
url.ParseUrl("https://www.chilkatsoft.com/readPost.asp")

# Connect to the web server
bAutoReconnect = True
success = rest.Connect(url.Host,url.Port,url.Ssl,bAutoReconnect)
if (success != True):
    print(rest.LastErrorText)
    sys.exit()

rest.AddQueryParam("name","John")
rest.AddQueryParam("age","33")

#  Send the HTTP POST.
success = rest.SendReqFormUrlEncoded("POST",url.Path)
if (success != True):
    print(rest.LastErrorText)
    sys.exit()

# Read the response header.
responseStatusCode = rest.ReadResponseHeader()
if (responseStatusCode < 0):
    print(rest.LastErrorText)
    sys.exit()

print("Response status code = " + str(responseStatusCode))

# We expect a 200 response status if the file data is coming.
# Otherwise, we'll get a string response body with an error message(or no response body).
if (responseStatusCode == 200):

    bodyStream = chilkat2.Stream()

    # The stream's sink will be a file.
    bodyStream.SinkFile = "qa_output/out.txt"

    # Read the response body to the stream.  Given that we've
    # set the stream's sink to a file, it will stream directly
    # to the file.
    success = rest.ReadRespBodyStream(bodyStream,True)
    if (success != True):
        print(rest.LastErrorText)
        sys.exit()

    print("Successfully streamed the response to a file.")

else:
    errResponse = rest.ReadRespBodyString()
    if (rest.LastMethodSuccess != True):
        print(rest.LastErrorText)
    else:
        print(errResponse)