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(Chilkat2-Python) HMAC Hex StringDemonstrates how to compute an HMAC using a hexidecimal key and data.
import sys import chilkat2 crypt = chilkat2.Crypt2() success = crypt.UnlockComponent("Anything for 30-day trial") if (success != True): print(crypt.LastErrorText) sys.exit() # Set the MAC algorithm to HMAC crypt.MacAlgorithm = "hmac" # Our HMAC key will be the bytes represented in the following hex string. # In other words, the HMAC key is composed of the bytes 0x41, 0xC2, 0x1C, ... # (It is not composed of the us-ascii string '4', '1', 'C', ...) keyHex = "41C21CB9D7A02FC5D4FADB9E4755B9DE" success = crypt.SetMacKeyEncoded(keyHex,"hex") # Our desire is to HMAC the bytes represented in the following string: dataHex = "C22078065B01460001000000010062043BF5B18228C8E02D17BCFE4E00561FA6DEC216EA97195CEB579942E275C21932258E3CD391E507FF4E7FD4C787A8447DA111C54A9C1795E7FF4C0BAA2EDA" # We'll need to decode the hex to binary: bd = chilkat2.BinData() bd.AppendEncoded(dataHex,"hex") # Do the HMAC-SHA256 hash and return as a hex string: crypt.EncodingMode = "hex" crypt.HashAlgorithm = "sha-256" macHex = crypt.MacBdENC(bd) print(macHex) |
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