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S3 - Upload to Bucket in a Region

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Demonstrates how to upload a file to an S3 bucket that was created in a particular region. AutoIt

Local $bSuccess = False

; This example requires the Chilkat API to have been previously unlocked.
; See Global Unlock Sample for sample code.

; When usig the REST class to access an S3 bucket that has been created in a particular region,
; there are three important things to remember:
; 
; 1) Connect to the domain that includes the region.  For example, instead of connecting to
;    "s3.amazonaws.com", connect to "s3.eu-central-1.amazonaws.com" if your bucket is in the EU Frankfurt region.
;    See http://docs.aws.amazon.com/general/latest/gr/rande.html#s3_region   for a list of S3 region domains (endpoints)
; 
; 2) Set the AuthAws.Region property equal to the region, such as "eu-central-1".
; 
; 3) Include the region in request's Host header.
; 

; This example will upload to a bucket in the eu-central-1 region.
; 
$oRest = ObjCreate("Chilkat.Rest")

; Connect to the Amazon AWS REST server.
Local $bTls = True
Local $iPort = 443
Local $bAutoReconnect = True
$bSuccess = $oRest.Connect("s3.eu-central-1.amazonaws.com",$iPort,$bTls,$bAutoReconnect)

; Provide AWS credentials for the REST call.
$oAuthAws = ObjCreate("Chilkat.AuthAws")
$oAuthAws.AccessKey = "AWS_ACCESS_KEY"
$oAuthAws.SecretKey = "AWS_SECRET_KEY"
$oAuthAws.ServiceName = "s3"
$oAuthAws.Region = "eu-central-1"
$bSuccess = $oRest.SetAuthAws($oAuthAws)

; Set the bucket name via the HOST header.
; In this case, the bucket name is "chilkateufrankfurt" (which was created in the eu-central-1 region)
$oRest.Host = "chilkateufrankfurt.s3.eu-central-1.amazonaws.com"

$oFileData = ObjCreate("Chilkat.BinData")
$bSuccess = $oFileData.LoadFile("qa_data/jpg/penguins.jpg")

; Upload the file to Amazon S3.
$oResponseBody = ObjCreate("Chilkat.StringBuilder")
$bSuccess = $oRest.FullRequestBd("PUT","/penguins.jpg",$oFileData,$oResponseBody)
If ($bSuccess <> True) Then
    ConsoleWrite($oRest.LastErrorText & @CRLF)
    Exit
EndIf

; Did we get a 200 response indicating success?
Local $iStatusCode = $oRest.ResponseStatusCode
If ($iStatusCode <> 200) Then
    ConsoleWrite("Error response: " & $oResponseBody.GetAsString() & @CRLF)
    ConsoleWrite("Status code: " & $iStatusCode & ", Status text: " & $oRest.ResponseStatusText & @CRLF)
    Exit
EndIf

ConsoleWrite("File successfully uploaded." & @CRLF)