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Get the Index of a JSON Member

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This example demonstrates how to get the index of a given member by name.
{
  "name": "donut",
  "image":
    {
    "fname": "donut.jpg",
    "w": 200,
    "h": 200
    },
  "thumbnail":
    {
    "fname": "donutThumb.jpg",
    "w": 32,
    "h": 32
    }
}

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Local $bSuccess = False

$oJson = ObjCreate("Chilkat.JsonObject")

; This is the above JSON with whitespace chars removed (SPACE, TAB, CR, and LF chars).
; The presence of whitespace chars for pretty-printing makes no difference to the Load
; method. 
Local $sJsonStr = "{""name"": ""donut"",""image"":{""fname"": ""donut.jpg"",""w"": 200,""h"": 200},""thumbnail"":{""fname"": ""donutThumb.jpg"",""w"": 32,""h"": 32}}"

$bSuccess = $oJson.Load($sJsonStr)
If ($bSuccess = False) Then
    ConsoleWrite($oJson.LastErrorText & @CRLF)
    Exit
EndIf

; The top-level JSON object has three members: name, image, and thumbnail.
Local $iNameIndex = $oJson.IndexOf("name")
; The index of the "name" member is 0.
ConsoleWrite("nameIndex = " & $iNameIndex & @CRLF)

Local $iThumbIndex = $oJson.IndexOf("thumbnail")
; The index of the "thumbnail" member is 2.
ConsoleWrite("thumbIndex = " & $iThumbIndex & @CRLF)

; The "fname" member is NOT a direct member of the top-level JSON object.
; It is a member of a nested object.  If we try to get the index of this
; member using the top-level JSON object, it is not found (and returns -1).
Local $iFnameIndex = $oJson.IndexOf("fname")
; The fnameIndex is -1 (not found).  This is correct.
ConsoleWrite("fnameIndex = " & $iFnameIndex & @CRLF)

; Get the "image" object.
$oImageObj = ObjCreate("Chilkat.JsonObject")
$oJson.ObjectOf2("image",$oImageObj)

; Now we can get the index of the "fname" object, because it is a direct
; member of the "image" object:
$iFnameIndex = $oImageObj.IndexOf("fname")
ConsoleWrite("fnameIndex = " & $iFnameIndex & @CRLF)