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(AutoIt) HTTP POST (Duplicate Simple HTML Form POST)Demonstrates how to duplicate a simple HTML form POST.
; This example requires the Chilkat API to have been previously unlocked. ; See Global Unlock Sample for sample code. $oReq = ObjCreate("Chilkat.HttpRequest") $oHttp = ObjCreate("Chilkat.Http") Local $bSuccess ; This example simulates this FORM: ; <form action="echoPost.asp" method="post"> ; First name: <input type="text" name="firstName"><br /> ; Last name: <input type="text" name="lastName"><br /> ; <input type="submit" value="Submit"> ; </form> ; The online FORM is found at this URL: ; https://www.chilkatsoft.com/simpleForm.html ; Build an HTTP POST Request: $oReq.HttpVerb = "POST" ; The FORM target is http://www.chilkatsoft.com/processPost.asp ; An easy way of filling out most of the HTTP request object ; is to call SetFromUrl: $oReq.SetFromUrl "https://www.chilkatsoft.com/echoPost.asp" ; Send form params using application/x-www-form-urlencoded $oReq.ContentType = "application/x-www-form-urlencoded" ; The only remaining task is to add the params to the ; HTTP request object: $oReq.AddParam "firstName","Matt" $oReq.AddParam "lastName","Jones" ; Send the HTTP POST and get the response. ; The POST is being sent to chilkatsoft.com, on port 443 (using TLS) Local $sDomain = "chilkatsoft.com" Local $iPort = 443 Local $bTls = True ; The HTTP POST is sent here: Local $oResp = $oHttp.SynchronousRequest($sDomain,$iPort,$bTls,$oReq) If ($oHttp.LastMethodSuccess = False) Then ConsoleWrite($oHttp.LastErrorText & @CRLF) Exit EndIf ; Display the HTML source of the page returned. ConsoleWrite($oResp.BodyStr & @CRLF) |
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