Classic ASP

GetChild* methods

Demonstrates several of the GetChild* methods.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

The output XML is this:

<abc b="pear" c="orange" a="130">Test</abc>

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Classic ASP

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
success = 0

set xml = Server.CreateObject("Chilkat.Xml")

' The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml")
If (success <> 1) Then
    Response.Write "<pre>" & Server.HTMLEncode( xml.LastErrorText) & "</pre>"
    Response.End
End If

' The NumChildren property contains the number of direct
' child nodes.  Note: The child nodes under "xyz" are NOT
' direct children of "root".  Therefore, the "root" node has
' 7 direct children
Response.Write "<pre>" & Server.HTMLEncode( "NumChildren = " & xml.NumChildren) & "</pre>"

' Iterate over the direct children by index. The first child
' is at index 0.

For i = 0 To xml.NumChildren - 1
    '  access the tag and content directly by index:
    Response.Write "<pre>" & Server.HTMLEncode( i & ": " & xml.GetChildTagByIndex(i) & " : " & xml.GetChildContentByIndex(i)) & "</pre>"

Next
Response.Write "<pre>" & Server.HTMLEncode( "-----") & "</pre>"

' Do the same as the above loop, but get the child node
' and access the Tag and Content properties:
For i = 0 To xml.NumChildren - 1
    ' child is a Chilkat.Xml
    Set child = xml.GetChild(i)
    Response.Write "<pre>" & Server.HTMLEncode( i & ": " & child.Tag & " : " & child.Content) & "</pre>"

Next
Response.Write "<pre>" & Server.HTMLEncode( "-----") & "</pre>"

' Do the same as the above loop, but instead of creating
' a new object instance for each child, call GetChild2 to
' update the object's reference instead.
For i = 0 To xml.NumChildren - 1
    ' Navigate to the Nth child.  
    success = xml.GetChild2(i)
    Response.Write "<pre>" & Server.HTMLEncode( i & ": " & xml.Tag & " : " & xml.Content) & "</pre>"
    ' Navigate back up to the parent:
    success = xml.GetParent2()
Next
Response.Write "<pre>" & Server.HTMLEncode( "-----") & "</pre>"

' Examine the result:
Response.Write "<pre>" & Server.HTMLEncode( xml.GetXml()) & "</pre>"

%>
</body>
</html>