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(Classic ASP) REST File Upload (multipart/form-data)Demonstrates how to upload a file using multipart/form-data.
<html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> </head> <body> <% ' This example requires the Chilkat API to have been previously unlocked. ' See Global Unlock Sample for sample code. ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.Rest") set rest = Server.CreateObject("Chilkat.Rest") ' Connect to the HTTP server using TLS. bTls = 1 port = 443 bAutoReconnect = 1 ' Make sure to replace "www.chilkatsoft.com" with your domain.. success = rest.Connect("www.chilkatsoft.com",port,bTls,bAutoReconnect) If (success <> 1) Then Response.Write "<pre>" & Server.HTMLEncode( rest.LastErrorText) & "</pre>" Response.End End If ' For versions of Chilkat < 10.0.0, use CreateObject("Chilkat_9_5_0.Stream") set fileStream = Server.CreateObject("Chilkat.Stream") fileStream.SourceFile = "qa_data/jpg/starfish.jpg" success = rest.AddHeader("Content-Type","multipart/form-data") rest.PartSelector = "1" success = rest.AddHeader("Content-Type","image/jpg") success = rest.AddHeader("Content-Disposition","form-data; name=""filename""; filename=""starfish.jpg""") success = rest.SetMultipartBodyStream(fileStream) rest.PartSelector = "0" responseBody = rest.FullRequestMultipart("POST","/the_uri_path_to_receive_the_upload") If (rest.LastMethodSuccess <> 1) Then Response.Write "<pre>" & Server.HTMLEncode( rest.LastErrorText) & "</pre>" Response.End End If If (rest.ResponseStatusCode <> 200) Then Response.Write "<pre>" & Server.HTMLEncode( "Received error response code: " & rest.ResponseStatusCode) & "</pre>" Response.End End If Response.Write "<pre>" & Server.HTMLEncode( "File uploaded") & "</pre>" %> </body> </html> |
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