Classic ASP

Parse the XML of an Excel (XLS) Spreadsheet

Demonstrate how to access various items from the XML of an XLS (Excel) Spreadsheet. Our sample data is shown below, and can be downloaded from http://www.chilkatsoft.com/data/ndc_nhric_labeler_codes_04_29_2015.xls

<?xml version="1.0" version="1.0" encoding="utf-8" ?>
<mso-application progid="Excel.Sheet"?>
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:x="urn:schemas-microsoft-com:office:excel" xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet" xmlns:html="http://www.w3.org/TR/REC-html40">
    <DocumentProperties xmlns="urn:schemas-microsoft-com:office:office">
        <Version>14.00</Version>
    </DocumentProperties>
    <OfficeDocumentSettings xmlns="urn:schemas-microsoft-com:office:office">
        <AllowPNG />
    </OfficeDocumentSettings>
    <ExcelWorkbook xmlns="urn:schemas-microsoft-com:office:excel">
        <WindowHeight>7800</WindowHeight>
        <WindowWidth>12000</WindowWidth>
        <WindowTopX>105</WindowTopX>
        <WindowTopY>105</WindowTopY>
        <ProtectStructure>False</ProtectStructure>
        <ProtectWindows>False</ProtectWindows>
    </ExcelWorkbook>
    <Styles>
        <Style ss:ID="Default" ss:Name="Normal">
            <Alignment ss:Vertical="Top" />
            <Borders />
            <Font ss:FontName="Arial" />
            <Interior />
            <NumberFormat />
            <Protection />
        </Style>
        <Style ss:ID="s63">
            <Alignment ss:Vertical="Bottom" ss:WrapText="1" />
            <Font ss:FontName="Arial" x:Family="Swiss" ss:Bold="1" />
            <Interior ss:Color="#C0C0C0" ss:Pattern="Solid" />
        </Style>
        <Style ss:ID="s64">
            <NumberFormat ss:Format="@" />
        </Style>
    </Styles>
    <Worksheet ss:Name="NDCLabelerCode">
        <Table ss:ExpandedColumnCount="2" ss:ExpandedRowCount="8186" x:FullColumns="1" x:FullRows="1">
            <Column ss:Index="2" ss:Width="580.5" />
            <Row ss:AutoFitHeight="0" ss:Height="38.25">
                <Cell ss:StyleID="s63">
                    <Data ss:Type="String">NDC Labeler Code</Data>
                </Cell>
                <Cell ss:StyleID="s63">
                    <Data ss:Type="String">Firm Name</Data>
                </Cell>
            </Row>
            <Row>
                <Cell ss:StyleID="s64">
                    <Data ss:Type="String">0002</Data>
                </Cell>
                <Cell ss:StyleID="s64">
                    <Data ss:Type="String">Eli Lilly and Company</Data>
                </Cell>
            </Row>
...

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<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
success = 0

set xlsDoc = Server.CreateObject("Chilkat.Xml")

success = xlsDoc.LoadXmlFile("myFiles/ndc_nhric_labeler_codes_04_29_2015.xls")
If (success <> 1) Then
    Response.Write "<pre>" & Server.HTMLEncode( xlsDoc.LastErrorText) & "</pre>"
    Response.End
End If

' This example will access the following pieces of data:
' NDC Labeler Code, Firm Name, 0002, Eli Lilly and Company, ...

' First navigate to the Worksheet named "NDCLabelerCode"
' xWorksheet is a Chilkat.Xml
Set xWorksheet = xlsDoc.GetChildWithAttr("Worksheet","ss:Name","NDCLabelerCode")

' Next, get the Table node:
' x is a Chilkat.Xml
Set x = xWorksheet.GetChildWithTag("Table")

' How many immediate child nodes?
numChildren = x.NumChildren

' Loop over each Row and access the cell contents.

For i = 0 To (numChildren - 1)

    ' Navigate without creating new XML objects
    success = x.GetChild2(i)

    If (x.TagEquals("Row")) Then

        data0 = x.ChilkatPath("Cell[0]|Data|*")
        Response.Write "<pre>" & Server.HTMLEncode( data0) & "</pre>"

        data1 = x.ChilkatPath("Cell[1]|Data|*")
        Response.Write "<pre>" & Server.HTMLEncode( data1) & "</pre>"
    End If

    ' Navigate back up.
    success = x.GetParent2()
Next


%>
</body>
</html>