Classic ASP
Parse Multipart Binary Http Response

This example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf.
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Classic ASP
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
success = 0

' This example requires the Chilkat API to have been previously unlocked.
' See Global Unlock Sample for sample code.

set http = Server.CreateObject("Chilkat.Http")
set req = Server.CreateObject("Chilkat.HttpRequest")

' ...
' Insert code here to construct some kind of HTTP request.
' this example is to show how to parse a particular kind of response.
' ...
' ...

' Send the request (whatever it may be in your case) to get the HTTP response object.
set resp = Server.CreateObject("Chilkat.HttpResponse")
success = http.HttpSReq("www.somedomain.com",443,1,req,resp)
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( http.LastErrorText) & "</pre>"
    Response.End
End If

' Get the response body (which is expected to be binary)
set respBody = Server.CreateObject("Chilkat.BinData")
success = resp.GetBodyBd(respBody)

' For this example, the response body contains something like this:

' ------=_Part_21302_2029949381.1547401515443
' Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
' Content-Transfer-Encoding: 8bit
' Content-ID: <rootpart@ws.jboss.org>
' 
' <env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'><env:Header></env:Header><env:Body>...</env:Body></env:Envelope>
' ------=_Part_21302_2029949381.1547401515443
' Content-Type: application/octet-stream
' Content-Transfer-Encoding: binary
' Content-Id: <fileArchivio-7d302908-4d64-43d3-bf4e-79ce806d43b3@ws.jboss.org>
' 
' BINARY_CONTENT_HERE...
' 
' ------=_Part_21302_2029949381.1547401515443--
' 

' Load it into a Chilkat MIME object.
set mime = Server.CreateObject("Chilkat.Mime")
success = mime.LoadMimeBd(respBody)
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( mime.LastErrorText) & "</pre>"
    Response.End
End If

numParts = mime.NumParts
If (numParts < 2) Then
    Response.Write "<pre>" & Server.HTMLEncode( "Expected multipart MIME with at least 2 sub-parts.") & "</pre>"
    Response.End
End If

' Get the 1st sub-part, which is the XML.

set part0 = Server.CreateObject("Chilkat.Mime")
success = mime.PartAt(0,part0)

' Should be OK because we checked NumParts above..
xmlStr = part0.GetBodyDecoded()
Response.Write "<pre>" & Server.HTMLEncode( xmlStr) & "</pre>"
Response.Write "<pre>" & Server.HTMLEncode( "----") & "</pre>"

' Save the 2nd part to a file.  (It is a .zip file in our test case..)

set part1 = Server.CreateObject("Chilkat.Mime")
success = mime.PartAt(1,part1)

success = part1.SaveBody("qa_output/attachedZip.zip")

' Alternatively, we could extract the binary data to a BinData and use elsewhere..
set zipData = Server.CreateObject("Chilkat.BinData")
success = part1.GetBodyBd(zipData)
success = zipData.WriteFile("qa_output/attachedZip_again.zip")

Response.Write "<pre>" & Server.HTMLEncode( "OK.") & "</pre>"

%>
</body>
</html>