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Android™

Iterate JSON where Member Names are Data Values

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Demonstrates how to parse JSON where member names are not keywords, but instead are data values.

Chilkat Android™ Downloads

Android™
// Important: Don't forget to include the call to System.loadLibrary
// as shown at the bottom of this code sample.
package com.test;

import android.app.Activity;
import com.chilkatsoft.*;

import android.widget.TextView;
import android.os.Bundle;

public class SimpleActivity extends Activity {

  private static final String TAG = "Chilkat";

  // Called when the activity is first created.
  @Override
  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    boolean success = false;

    CkJsonObject json = new CkJsonObject();

    success = json.LoadFile("qa_data/json/valuesAsNames.json");

    // Imagine we have JSON such as the following:

    // {
    //   "1680": {
    //     "entity_id": "1680",
    //     "type_id": "simple",
    //     "sku": "123"
    //   },
    //   "1701": {
    //     "entity_id": "1701",
    //     "type_id": "simple",
    //     "sku": "456"
    //   }
    // }
    // 

    // This presents a parsing problem because the member names, such as "1680"
    // are not keywords.  Instead they are data values.  We don't know what they
    // may be in advance.  

    // To solve, we iterate over the members, get the name of each, ...
    int numMembers = json.get_Size();
    int i;
    for (i = 0; i <= numMembers - 1; i++) {

        String name = json.nameAt(i);

        Log.i(TAG, name + ":");
        CkJsonObject jRecord = json.ObjectAt(i);

        Log.i(TAG, "entity_id: " + jRecord.stringOf("entity_id"));
        Log.i(TAG, "type_id: " + jRecord.stringOf("type_id"));
        Log.i(TAG, "sku: " + jRecord.stringOf("sku"));

        }


  }

  static {
      System.loadLibrary("chilkat");

      // Note: If the incorrect library name is passed to System.loadLibrary,
      // then you will see the following error message at application startup:
      //"The application <your-application-name> has stopped unexpectedly. Please try again."
  }
}