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(Java) XML Sort Records by ContentDemonstrates the SortRecordsByContent method. The input XML, available at http://www.chilkatsoft.com/data/fruitRecordsSort.xml, is this: <root> <fruits> <fruit> <name>apple</name> <color>red</color> </fruit> <fruit> <name>banana</name> <color>yellow</color> </fruit> <fruit> <name>blackberry</name> <color>purple</color> </fruit> <fruit> <name>blueberry</name> <color>blue</color> </fruit> <fruit> <name>orange</name> <color>orange</color> </fruit> <fruit> <name>pear</name> <color>green</color> </fruit> </fruits> </root>
import com.chilkatsoft.*; public class ChilkatExample { static { try { System.loadLibrary("chilkat"); } catch (UnsatisfiedLinkError e) { System.err.println("Native code library failed to load.\n" + e); System.exit(1); } } public static void main(String argv[]) { CkXml xml = new CkXml(); CkXml xSortRoot; boolean success; // The sample input XML is available at http://www.chilkatsoft.com/data/fruitRecordsSort.xml success = xml.LoadXmlFile("fruitRecordsSort.xml"); if (success != true) { System.out.println(xml.lastErrorText()); return; } // The "fruit" records are direct children of the "fruits" node. // Therefore, to sort the fruit records, the SortRecordsByContent // method must be called from the "fruits" node. xSortRoot = xml.FindChild("fruits"); // Sort by the "name" field in ascending order. boolean bAscending = true; xSortRoot.SortRecordsByContent("name",bAscending); // Show the result: System.out.println(xml.getXml()); // <root> // <fruits> // <fruit> // <name>apple</name> // <color>red</color> // </fruit> // <fruit> // <name>banana</name> // <color>yellow</color> // </fruit> // <fruit> // <name>blackberry</name> // <color>purple</color> // </fruit> // <fruit> // <name>blueberry</name> // <color>blue</color> // </fruit> // <fruit> // <name>orange</name> // <color>orange</color> // </fruit> // <fruit> // <name>pear</name> // <color>green</color> // </fruit> // </fruits> // </root> } } |
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