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(Java) GetChild* methodsDemonstrates several of the GetChild* methods. The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this: <root> <fruit color="red">apple</fruit> <fruit color="green">pear</fruit> <veg color="orange">carrot</veg> <meat animal="cow">beef</meat> <xyz> <fruit color="blue">blueberry</fruit> <veg color="green">broccoli</veg> </xyz> <fruit color="purple">grape</fruit> <cheese color="yellow">cheddar</cheese> </root> The output XML is this: <abc b="pear" c="orange" a="130">Test</abc>
import com.chilkatsoft.*; public class ChilkatExample { static { try { System.loadLibrary("chilkat"); } catch (UnsatisfiedLinkError e) { System.err.println("Native code library failed to load.\n" + e); System.exit(1); } } public static void main(String argv[]) { CkXml xml = new CkXml(); CkXml child; boolean success; // The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml success = xml.LoadXmlFile("get_child.xml"); if (success != true) { System.out.println(xml.lastErrorText()); return; } // The NumChildren property contains the number of direct // child nodes. Note: The child nodes under "xyz" are NOT // direct children of "root". Therefore, the "root" node has // 7 direct children System.out.println("NumChildren = " + xml.get_NumChildren()); // Iterate over the direct children by index. The first child // is at index 0. int i; for (i = 0; i <= xml.get_NumChildren() - 1; i++) { // access the tag and content directly by index: System.out.println(i + ": " + xml.getChildTagByIndex(i) + " : " + xml.getChildContentByIndex(i)); } System.out.println("-----"); // Do the same as the above loop, but get the child node // and access the Tag and Content properties: for (i = 0; i <= xml.get_NumChildren() - 1; i++) { child = xml.GetChild(i); System.out.println(i + ": " + child.tag() + " : " + child.content()); } System.out.println("-----"); // Do the same as the above loop, but instead of creating // a new object instance for each child, call GetChild2 to // update the object's reference instead. for (i = 0; i <= xml.get_NumChildren() - 1; i++) { // Navigate to the Nth child. success = xml.GetChild2(i); System.out.println(i + ": " + xml.tag() + " : " + xml.content()); // Navigate back up to the parent: success = xml.GetParent2(); } System.out.println("-----"); // Examine the result: System.out.println(xml.getXml()); } } |
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