(Java) DNS Query SOA Records

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Shows how to perform a DNS query to retrieve SOA records.

Note: This example requires Chilkat v9.5.0.96 or later.

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import com.chilkatsoft.*;

public class ChilkatExample {

  static {
    try {
        System.loadLibrary("chilkat");
    } catch (UnsatisfiedLinkError e) {
      System.err.println("Native code library failed to load.\n" + e);
      System.exit(1);
    }
  }

  public static void main(String argv[])
  {
    CkDns dns = new CkDns();

    CkJsonObject json = new CkJsonObject();
    json.put_EmitCompact(false);

    boolean success = dns.Query("SOA","x.com",json);
    if (success == false) {
        System.out.println(dns.lastErrorText());
        return;
        }

    System.out.println(json.emit());

    // Sample response.
    // Parsing code below..

    // {
    //   "answer": {
    //     "soa": [
    //       {
    //         "name": "x.com",
    //         "ttl": 1800,
    //         "mname": "alexia.ns.cloudflare.com",
    //         "rname": "dns.cloudflare.com",
    //         "serial": -1971124188,
    //         "refresh": 10000,
    //         "retry": 2400,
    //         "expire": 604800,
    //         "minttl": 1800
    //       }
    //     ]
    //   }
    // }

    // Use this online tool to generate parsing code from sample JSON: 
    // Generate Parsing Code from JSON

    String name;
    int ttl;
    String mname;
    String rname;
    int serial;
    int refresh;
    int retry;
    int expire;
    int minttl;

    int i = 0;
    int count_i = json.SizeOfArray("answer.soa");
    while (i < count_i) {
        json.put_I(i);
        name = json.stringOf("answer.soa[i].name");
        ttl = json.IntOf("answer.soa[i].ttl");
        mname = json.stringOf("answer.soa[i].mname");
        rname = json.stringOf("answer.soa[i].rname");
        serial = json.IntOf("answer.soa[i].serial");
        refresh = json.IntOf("answer.soa[i].refresh");
        retry = json.IntOf("answer.soa[i].retry");
        expire = json.IntOf("answer.soa[i].expire");
        minttl = json.IntOf("answer.soa[i].minttl");
        i = i+1;
        }
  }
}