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(C#) Duplicate TLS 1.2 SOAP Request that uses .NET HttpWebRequestThis example shows how to duplicate a SOAP request that uses .NET's HttpWebRequest and requires TLS 1.2. string xmlRequest = "...envelope..." System.Net.ServicePointManager.SecurityProtocol = (SecurityProtocolType)3072; string url = "https://www3.gsis.gr/webtax2/wsgsis/RgWsPublic/RgWsPublicPort?WSDL"; HttpWebRequest req = (HttpWebRequest)WebRequest.Create(url); req.Method = "POST"; req.ContentType = "text/xml;charset=UTF-8"; byte[] reqBytes = new System.Text.UTF8Encoding().GetBytes(xmlRequest); req.ContentLength = reqBytes.Length; try { using (System.IO.Stream reqStream = req.GetRequestStream()) { reqStream.Write(reqBytes, 0, reqBytes.Length); reqStream.Flush(); reqStream.Close(); } } catch (Exception ex) { actionLogger.AddError(ex.Message, null); actionLogger.Validate(); } string xmlResponse = null; using (HttpWebResponse resp = (HttpWebResponse)req.GetResponse()) { try { using (System.IO.StreamReader sr = new System.IO.StreamReader(resp.GetResponseStream())) { xmlResponse = sr.ReadToEnd(); sr.Close(); } } catch (Exception ex) { actionLogger.AddError(ex.Message, null); actionLogger.Validate(); } finally { resp.Close(); } }
// This example assumes Chilkat HTTP to have been previously unlocked. // See Global Unlock Sample for sample code. bool success; Chilkat.Http http = new Chilkat.Http(); Chilkat.HttpRequest req = new Chilkat.HttpRequest(); req.HttpVerb = "POST"; req.ContentType = "text/xml"; req.SendCharset = true; req.Charset = "utf-8"; req.Path = "/webtax2/wsgsis/RgWsPublic/RgWsPublicPort?WSDL"; string xmlRequest = "...SOAP envelope..."; req.LoadBodyFromString(xmlRequest); http.FollowRedirects = true; // Chilkat will automatically offer TLS 1.2. It is the server that // chooses the TLS protocol version. Assuming the server wishes to use // TLS 1.2, then that is what will be used. Chilkat.HttpResponse resp = http.SynchronousRequest("www3.gsis.gr",443,true,req); if (http.LastMethodSuccess != true) { Debug.WriteLine(http.LastErrorText); return; } string xmlResponse = resp.BodyStr; Debug.WriteLine(xmlResponse); |
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