Visual Basic 6.0
Visual Basic 6.0
GetChild* methods
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Demonstrates several of the GetChild* methods.The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:
<root>
<fruit color="red">apple</fruit>
<fruit color="green">pear</fruit>
<veg color="orange">carrot</veg>
<meat animal="cow">beef</meat>
<xyz>
<fruit color="blue">blueberry</fruit>
<veg color="green">broccoli</veg>
</xyz>
<fruit color="purple">grape</fruit>
<cheese color="yellow">cheddar</cheese>
</root>
The output XML is this:
<abc b="pear" c="orange" a="130">Test</abc>
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Dim success As Long
success = 0
Dim xml As New ChilkatXml
Dim child As ChilkatXml
' The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
success = xml.LoadXmlFile("get_child.xml")
If (success <> 1) Then
Debug.Print xml.LastErrorText
Exit Sub
End If
' The NumChildren property contains the number of direct
' child nodes. Note: The child nodes under "xyz" are NOT
' direct children of "root". Therefore, the "root" node has
' 7 direct children
Debug.Print "NumChildren = " & xml.NumChildren
' Iterate over the direct children by index. The first child
' is at index 0.
Dim i As Long
For i = 0 To xml.NumChildren - 1
' access the tag and content directly by index:
Debug.Print i & ": " & xml.GetChildTagByIndex(i) & " : " & xml.GetChildContentByIndex(i)
Next
Debug.Print "-----"
' Do the same as the above loop, but get the child node
' and access the Tag and Content properties:
For i = 0 To xml.NumChildren - 1
Set child = xml.GetChild(i)
Debug.Print i & ": " & child.Tag & " : " & child.Content
Next
Debug.Print "-----"
' Do the same as the above loop, but instead of creating
' a new object instance for each child, call GetChild2 to
' update the object's reference instead.
For i = 0 To xml.NumChildren - 1
' Navigate to the Nth child.
success = xml.GetChild2(i)
Debug.Print i & ": " & xml.Tag & " : " & xml.Content
' Navigate back up to the parent:
success = xml.GetParent2()
Next
Debug.Print "-----"
' Examine the result:
Debug.Print xml.GetXml()