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Lianja

HTTP POST and Stream Response to File

See more REST Examples

Demonstrates how to send an HTTP POST and stream the response body directly to a file.

Chilkat Lianja Downloads

Lianja
llSuccess = .F.

// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.

loRest = createobject("CkRest")

loUrl = createobject("CkUrl")
// This URL will emit a response that echos the query params (name and age)
loUrl.ParseUrl("https://www.chilkatsoft.com/readPost.asp")

// Connect to the web server
llBAutoReconnect = .T.
llSuccess = loRest.Connect(loUrl.Host,loUrl.Port,loUrl.Ssl,llBAutoReconnect)
if (llSuccess <> .T.) then
    ? loRest.LastErrorText
    release loRest
    release loUrl
    return
endif

loRest.AddQueryParam("name","John")
loRest.AddQueryParam("age","33")

//  Send the HTTP POST.
llSuccess = loRest.SendReqFormUrlEncoded("POST",loUrl.Path)
if (llSuccess <> .T.) then
    ? loRest.LastErrorText
    release loRest
    release loUrl
    return
endif

// Read the response header.
lnResponseStatusCode = loRest.ReadResponseHeader()
if (lnResponseStatusCode < 0) then
    ? loRest.LastErrorText
    release loRest
    release loUrl
    return
endif

? "Response status code = " + str(lnResponseStatusCode)

// We expect a 200 response status if the file data is coming.
// Otherwise, we'll get a string response body with an error message(or no response body).
if (lnResponseStatusCode = 200) then

    loBodyStream = createobject("CkStream")

    // The stream's sink will be a file.
    loBodyStream.SinkFile = "qa_output/out.txt"

    // Read the response body to the stream.  Given that we've
    // set the stream's sink to a file, it will stream directly
    // to the file.
    llSuccess = loRest.ReadRespBodyStream(loBodyStream,.T.)
    if (llSuccess <> .T.) then
        ? loRest.LastErrorText
        release loRest
        release loUrl
        release loBodyStream
        return
    endif

    ? "Successfully streamed the response to a file."

else
    lcErrResponse = loRest.ReadRespBodyString()
    if (loRest.LastMethodSuccess <> .T.) then
        ? loRest.LastErrorText
    else
        ? lcErrResponse
    endif

endif



release loRest
release loUrl
release loBodyStream