Lianja

Duplicate PHP RSA Encryption

See more RSA Examples

Demonstrates how to duplicate the following PHP function. Lianja

llSuccess = .F.

// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.

// Duplicate the following PHP code:
// 
//    public function encryptRSA($plainText,$rsaMOD,$pubKEY){
//         $rsa  = new RSA();
//         $rsa->setEncryptionMode(RSA::ENCRYPTION_PKCS1);
//         $publicKey = [
//             'e' => new BigInteger($pubKEY,16),
//             'n' => new BigInteger($rsaMOD,16)
//         ];
// 		
//         $rsa->loadKey($publicKey);
//         $ciphertext = $rsa->encrypt($plainText);
//         return bin2hex($ciphertext);
//     }
// 
//     $plainText="key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
//     $rsaMOD="F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"
//     $pubKEY="010001"

// We have the RSA modulus in hex
lcRsaMOD = "F0946D8F05604809E24B8CFFD30349CEA9E5F4D320BFD9E9AA1B088863F02C43E7997D37A3E27B4F8F359F1744DB6B20A437067C0D325A80660D12FF56A57673"

// The RSA exponent in hex is "010001", which is 65537 in decimal.  It's typically the exponent that is always used.
lcRsaEXP = "010001"

// Get the RSA modulus and exponent in base64.
loBdMod = createobject("CkBinData")
loBdExp = createobject("CkBinData")
llSuccess = loBdMod.AppendEncoded(lcRsaMOD,"hex")
llSuccess = loBdExp.AppendEncoded(lcRsaEXP,"hex")

// Build the XML representation of the RSA public key
loXml = createobject("CkXml")
loXml.Tag = "RSAPublicKey"
loXml.UpdateChildContent("Modulus",loBdMod.GetEncoded("base64"))
loXml.UpdateChildContent("Exponent",loBdExp.GetEncoded("base64"))

// Load the RSA public key into a Chilkat public key object.
loPubkey = createobject("CkPublicKey")
llSuccess = loPubkey.LoadFromString(loXml.GetXml())

// Setup the RSA object for encryption and do it..
loRsa = createobject("CkRsa")
loRsa.VerboseLogging = .T.
llSuccess = loRsa.UsePublicKey(loPubkey)

// Use PKCSv1.5 padding
loRsa.PkcsPadding = .T.

// Encrypt and return the string as hex.
loRsa.EncodingMode = "hex"
lcPlainText = "key=abcdefghijkmnopq&iv=abcdefghijkmnopq&h=12345678&s=12345678"
lcCipherText = loRsa.EncryptStringENC(lcPlainText,.F.)
if (loRsa.LastMethodSuccess = .F.) then
    ? loRsa.LastErrorText
    release loBdMod
    release loBdExp
    release loXml
    release loPubkey
    release loRsa
    return
endif

// Note: The PKCSv1_5 padding incorporates random bytes.  Therefore, the RSA encryption will produce different results each time -- all of which are valid 
// and decrypt correctly to the same original text.
? lcCipherText


release loBdMod
release loBdExp
release loXml
release loPubkey
release loRsa